This prints out “1″:
begin a = 1 raise RuntimeError, "foo" rescue => e puts a end
I would think that a would be out of scope inside the rescue section but I guess Ruby considers the rescue section part of the begin/end block?
Tags: Ruby · Software
1 Adam Keys // May 22, 2008 at 5:38 pm
This is probably related to the situation where
5.times { a = 4 } puts a
used to print 4.
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1 Adam Keys // May 22, 2008 at 5:38 pm
This is probably related to the situation where
5.times { a = 4 }
puts a
used to print 4.
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